Swagger2匹配多个controller代码实例
导读
方法一:使用多个controller的共同拥有的父类,即精确到两个controller的上一级
@Bean public Docket createRestApi() { return new Docket(DocumentationType.SWAGGER_2) .apiInfo(apiInfo()) .select() .apis(RequestHandlerSelectors.basePackage("com.shubing")) .paths(PathSelectors.any()) .build(); }
方法二:指定所有controller的都实现的一个接口,比如@RestController
@Bean public Docket createRestApi() { return new Docket(DocumentationType.SWAGGER_2) .apiInfo(apiInfo()) .select() .apis(RequestHandlerSelectors.withClassAnnotation(RestController.class)) .paths(PathSelectors.any()) .build(); }
使用以下两种,都是错误的
@Bean public Docket createRestApi() { return new Docket(DocumentationType.SWAGGER_2) .apiInfo(apiInfo()) .select() .apis(RequestHandlerSelectors.basePackage("com.shubing.*.controller")) .paths(PathSelectors.any()) .build(); } @Bean public Docket createRestApi() { return new Docket(DocumentationType.SWAGGER_2) .apiInfo(apiInfo()) .select() .apis(RequestHandlerSelectors.basePackage("com.shubing.course.controller")) .apis(RequestHandlerSelectors.basePackage("com.shubing.user.controller")) .paths(PathSelectors.any()) .build(); }
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